ICSE Class X Math 2015 Solved Paper

ABC is a right angled triangle with ∠ABC= 90∘.D is any point on AB and DE is perpendicular to AC. Prove that :

Question : 47

Total: 52

△ADE∼△ACB.

Solution:

To Prove : △ADE∼△ACB
(i) In △ADE and △ACB
‌ (1) ‌‌‌∠A‌=∠A‌‌‌ [common] ‌
(2) ∠AED‌=∠ABC
‌=90∘‌ (given) ‌
∴△ADE∼△ACB [AA axiom]

Go to Question:

Prev Question

Next Question