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ICSE Class X Math 2015 Solved Paper

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ABC is a right angled triangle with ∠ABC= 90∘.D is any point on AB and DE is perpendicular to AC. Prove that :
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Question : 49
Total: 52
Find, area of △ADE : area of quadrilateral BCED.
Solution:  
‌‌
‌ Ar. of ‌(△ABC)
‌ Ar. of ‌(△ADE)
=‌
AB2
AE2
 =‌
144
16
=‌
9
1

‌‌
‌ Ar. of ‌(△ADE)+Ar‌. of ‌(BCED)
Ar‌. of ‌(△ADE)
=9
‌1+‌
‌ Ar. of ‌(BCED)
‌ Ar. of ‌(△ADE)
=9
‌‌
‌ Ar. of ‌(△ADE)
‌ Ar. of ‌(BCED)
=‌
1
8
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