ICSE Class X Math 2016 Solved Paper

In the given figure below, AD is a diameter. O is the centre of the circle. AD is parallel to BC and ∠CBD=32∘. Find:

Question : 11

Total: 57

∠BED

Solution:

In △ABD
∠ABD=‌90∘
‌(‌ angle in a semicircle) ‌
∠ADB=‌32∘
∠BAD=‌180−(90+32)
=‌58∘.
∠BAD=‌∠BED
(angle in the same segment)

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