ICSE Class X Math 2016 Solved Paper

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Question : 20
Total: 57
SECTION - II

Solve the quadratic equation x23(x+3)= 0 ; Give your answer correct to two significant figures.
Solution:  
Given : x23(x+3)=0
x23x9=0
Comparing x23x9=0 with ax2+bx+c =0, we get
We know,
a=1,b=3,c=9
x=
b±b24ac
2a

=
(3)±(3)24×1×(9)
2×1

=
3±9+36
2
=
3±45
2

=
3±35
2
=
3±3×2.236
2

x=
3±6.708
2

x=
3+6.708
2
and
36.708
2

x=4.85, and 1.85
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