ICSE Class X Math 2016 Solved Paper

In the given figure below, AD is a diameter. O is the centre of the circle. AD is parallel to BC and ∠CBD=32∘. Find:

Question : 9

Total: 57

∠OBD

Solution:

Given : AD∥BC
‌∴‌‌∠ADB=∠DBC=32∘ ‌‌ (alternate angles) ‌
‌OB=OD‌ (radii of the circle) ‌
‌∴∠OBD=32∘
(angles opposite to equal sides of a triangle)

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