NCERT Class XI Chemistry Classification of Elements and Periodicity in Properties Solutions
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Question : 30
Total: 40
Assign the position of the element having outer electronic configuration
(i)n s 2 n p 4 for n = 3
(ii) (n – 1)d 2 n s 2 for n = 4, and
(iii) (n – 2)f 7 (n – 1) d 1 n s 2 for n = 6, in the periodic table.
(i)
(ii) (n – 1)
(iii) (n – 2)
Solution:
(i) n s 2 n p 4 For n = 3 ; outer electronic configuration = 3 s 2 3 p 4
∴ The element will be in 3rd period, 16th group and p-block (Sulphur).
(ii) (n – 1)d 2 n s 2
For n = 4 ; outer electronic configuration =3 d 2 4 s 2
∴ The element will be in 4th period, 4th group and d-block (Titanium).
(iii) (n – 2)f 7 (n – 1) d 1 n s 2
For n = 6 ; the outer electronic configuration is4 f 7 5 d 1 6 s 2 .
∴ The element will be in 6th period, 3rd group and f-block (Gadolinium).
∴ The element will be in 3rd period, 16th group and p-block (Sulphur).
(ii) (n – 1)
For n = 4 ; outer electronic configuration =
∴ The element will be in 4th period, 4th group and d-block (Titanium).
(iii) (n – 2)
For n = 6 ; the outer electronic configuration is
∴ The element will be in 6th period, 3rd group and f-block (Gadolinium).
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