NCERT Class XI Chemistry Classification of Elements and Periodicity in Properties Solutions

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Question : 30
Total: 40
Assign the position of the element having outer electronic configuration
(i) ns2np4 for n = 3
(ii) (n – 1) d2ns2 for n = 4, and
(iii) (n – 2) f7 (n – 1) d1ns2 for n = 6, in the periodic table.
Solution:  
(i) ns2np4 For n = 3 ; outer electronic configuration = 3s23p4
∴ The element will be in 3rd period, 16th group and p-block (Sulphur).
(ii) (n – 1) d2ns2
For n = 4 ; outer electronic configuration = 3d24s2
∴ The element will be in 4th period, 4th group and d-block (Titanium).
(iii) (n – 2) f7 (n – 1) d1ns2
For n = 6 ; the outer electronic configuration is 4f75d16s2.
∴ The element will be in 6th period, 3rd group and f-block (Gadolinium).
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