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NCERT Class XI Chemistry Equilibrium Solutions

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Question : 10
Total: 73
At 450 K, Kp = 2.0 × 1010∕bar for the given reaction at equilibrium.
2SO2(g)+O2(g) ⇌ 2SO3(g)
What is Kc at this temperature?
Solution:  
Kp = Kc(RT)Δng or Kc =
Kp
(RT)Δng
Δng = 2 – (2 + 1) = –1, T = 450 K, R = 0.083 bar LK–1mol–1
∴ Kc =
2.0×1010
(0.083×450)−1
 = 2.0 × 1010 × (0.083 × 450) = 7.47 × 1011M−1
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