NCERT Class XI Chemistry Equilibrium Solutions

Question : 20

Total: 73

One of the reaction that takes place in producing steel from iron ore is the reduction of iron(II) oxide by carbon monoxide to give iron metal and CO2.
FeO(s)+CO(g) ⇌ Fe(s)+CO2(g) ; Kp = 0.265 atm at 1050 K
What are the equilibrium partial pressures of CO and CO2 at 1050 K if the partial pressures are : pCO = 1.4 atm and pCO2 = 0.80 atm?

Solution:

FeO(s)+CO(g) ⇌ Fe(s)+CO2(g)

Initial‌pressures	1.4‌atm	0.80‌atm
Pressure‌at‌equilibrium	1.4−p	0.80+p

∴ equilibrium, pCO2 = (0.80 + p) atm, pCO = (1.4 – p) atm
Kp =

pCO2

pCO

⇒ 0.265 =

0.80+p

1.4−p

or, 0.265 (1.4 – p) = 0.80 + p
or, 0.371 – 0.265p = 0.80 + p
or, 1.265p = – 0.429 or, p = –0.339 atm
∴ (pCO)eq = 1.4 + 0.339 atm = 1.739 atm
(pCO2)eq = 0.80 – 0.339 atm = 0.461 atm

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