NCERT Class XI Chemistry Equilibrium Solutions

Question : 50

Total: 73

The degree of ionization of a 0.1 M bromoacetic acid solution is 0.132. Calculate the pH of the solution and pKa of bromoacetic acid.

Solution:

CH2

−COOH ⇌

CH2

−COO−+H+

Initial‌molar‌conc.	C	0	0
Eqm.molar‌conc.	C(1−α)	Cα	Cα

C = 0.1 M, a = 0.132, [H+] = Ca = 0.0132 M
pH = – log(0.0132) = 1.8794
Ka = Ca2 or Ka = 0.1 × (0.132)2 = 1.74 × 10–3
pKa = –log Ka = – log(1.74 × 10–3) = 2.7595

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