NCERT Class XI Chemistry Organic Chemistry Some basic principles and Techniques Solutions
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Question : 35
Total: 40
In the estimation of sulphur by Carius method, 0.468 g of an organic sulphur compound afforded 0.668 g of barium sulphate. Find out the percentage of sulphur in the given compound.
Solution:
Given : Mass of organic sulphur compound = 0.468 g
Mass ofB a S O 4 = 0.668 g; 1 mol of B a S O 4 = 233 g
233 g ofB a S O 4 contains 32 g of S
∴ 0.668 g ofB a S O 4 contains
= 0.09174 g
0.09174 g S is present in 0.468 g of the compound.
% of S in compound =
× 100 = 19.6 %
Mass of
233 g of
∴ 0.668 g of
0.09174 g S is present in 0.468 g of the compound.
% of S in compound =
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