NCERT Class XI Chemistry Organic Chemistry Some basic principles and Techniques Solutions
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Question : 6
Total: 40
Draw formulas for the first five members of each homologous series beginning with the following compounds.
(a) H–COOH (b)C H 3 C O C H 3 H – C H = C H 2
(a) H–COOH (b)
Solution:
(a) : HCOOH
The given compound is formic acid (a carboxylic acid) and the first five members of the carboxylic acid series are :
(1) HCOOH
(2)C H 3 C O O H
(3)C H 3 C H 2 C O O H
(4)C H 3 C H 2 C H 2 C O O H
(5)C H 3 C H 2 C H 2 C H 2 C O O H
(b) :C H 3 C O C H 3
The given compound, propanone, is a ketone and the first five members of the ketone series are :
(1)C H 3 C O C H 3
(2)C H 3 C H 2 C O C H 3
(3)C H 3 C H 2 C H 2 C O C H 3
(4)C H 3 C H 2 C H 2 C H 2 C O C H 3
(5)C H 3 C H 2 C H 2 C H 2 C H 2 C O C H 3
(c) :C H 2 = C H 2
Ethene is an alkene and the first five members of the alkene series are :
(1)C H 2 = C H 2
(2)C H 3 – C H = C H 2
(3)C H 3 C H 2 — C H = C H 2
(4)C H 3 C H 2 C H 2 — C H = C H 2
(5)C H 3 C H 2 C H 2 C H 2 − C H = C H 2
The given compound is formic acid (a carboxylic acid) and the first five members of the carboxylic acid series are :
(1) HCOOH
(2)
(3)
(4)
(5)
(b) :
The given compound, propanone, is a ketone and the first five members of the ketone series are :
(1)
(2)
(3)
(4)
(5)
(c) :
Ethene is an alkene and the first five members of the alkene series are :
(1)
(2)
(3)
(4)
(5)
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