NCERT Class XI Chemistry Solutions

Question : 36

Total: 40

Compare the relative stability of the following species and indicate their magnetic properties; O2 , O2+ , O2– (superoxide), O22– (peroxide).

Solution:

Species

Total electrons

Configuration

Bond order

Magnetic character

KKσ(2s)2σ*(2s)2σ(2pz)2π(2px)2 = π(2py)2π*(2px)1 = π*(2py)1

(8−4)

= 2.0

Paramagnetic

O2+

KKσ(2s)2σ*(2s)2σ(2pz)2π(2px)2 = π(2py)2π*(2px)1

(8−3)

= 2.5

Paramagnetic

O2−

KKσ(2s)2σ*(2s)2σ(2pz)2π(2px)2 = π(2py)2π*(2px)2 = π*(2py)1

(8−5)

= 1.5

Paramagnetic

O22−

KKσ(2s)2σ*(2s)2σ(2pz)2π(2px)2 = π(2py)2π*(2px)2 = π*(2py)2

(8−6)

= 1.0

Diamagnetic

∴ Relative order of stability is O2+%>O_2>O_2^{–}>O_2^{2–}$.

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