NCERT Class XI Chemistry Some Basic Concepts of Chemistry Solutions

Question : 28

Total: 36

Which one of the following will have largest number of atoms?
(i) 1 g Au(s)
(ii) 1 g Na(s)
(iii) 1 g Li(s)
(iv) 1 g of Cl2(g)

Solution:

(i) No. of atoms in 1 g of Au =

197

× 6.022 × 1023 = 3.057 × 1021 atoms
(ii) No. of atoms in l g of Na =

× 6.022 × 1023 = 2.618 × 1022 atoms
(iii) No. of atoms in l g of Li =

× 6.022 × 1023 = 8.604 × 1022 atoms
(iv) No. of atoms in 1 g of Cl2 =

× 2 × 6.022 × 1023 = 1.697 × 1022 atoms
Thus, 1 g of Li has largest number of atoms.

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