NCERT Class XI Chemistry Some Basic Concepts of Chemistry Solutions

Question : 35

Total: 36

Calcium carbonate reacts with aqueous HCI to give CaCl2 and CO2 according to the reaction,
CaCO3(s)+2HCl(aq) → CaCl2(aq)+CO2(g)+H2O(l).
What mass of CaCO3 is required to react completely with 25 mL of 0.75 M HCl?

Solution:

CaCO3(s)+2HCl(aq) → CaCl2(aq)+CO2(g)+H2O(l)
No. of moles of HCl given = MHClVHCl = 0.75 mole L–1 × 25 × 10–3 L
= 18.75 × 10–3 mole = 0.0188 mole
2 moles of HCl requires 1 mole of CaCO3
0.0188 mole of HCl will require =

0.0188

= 0.0094 mole of CaCO3
Molar mass of CaCO3 = 100 g/mole
Mass of CaCO3 required = 100 × 0.0094 = 0.94 g

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