NCERT Class XI Chemistry Some Basic Concepts of Chemistry Solutions

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Question : 6
Total: 36
Calculate the concentration of nitric acid in moles per litre in a sample which has a density, 1.41 gmL1 and the mass per cent of nitric acid in it being 69%.
Solution:  
69 mass per cent of nitric acid means that 69 g of HNO3 is present in 100 g of solution.
∴ Volume of solution =
Mass
Density
=
100g
1.41gmL1
= 70.92 mL
Moles of HNO3 =
69
63
= 1.095
Molarity =
MolesofHNO3
Volumeofsoln.inmL
× 1000 =
1.095
70.92
× 1000 = 15.44 M
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