NCERT Class XI Chemistry States of Matter Solutions
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Question : 5
Total: 23
Pressure of 1 g of an ideal gas A at 27°C is found to be 2 bar. When 2 g of another ideal gas B is introduced in the same flask at same temperature the pressure becomes 3 bar. Find a relationship between their molecular masses.
Solution:
For gas A, P A V =
RT ... (1)
For gas B,P B V =
RT ... (ii)
Dividing equation (1) by equation (2) gives
=
P A + P B = 3 ⇒ P B = 3 - 2 = 1 bar
= (
) (
) = (
) (
) ⇒
= 1 : 4
For gas B,
Dividing equation (1) by equation (2) gives
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