NCERT Class XI Chemistry Structure of Atom Solutions

Question : 37

Total: 67

The diameter of zinc atom is 2.6 Å. Calculate (a) radius of zinc atom in pm and (b) number of atoms present in a length of 1.6 cm if the zinc atoms are arranged side by side lengthwise.

Solution:

(a) Radius of zinc =

diameter

2.6

= 1.3 Å = 1.3 × 10–10 m
= 130 × 10–12 m = 130 pm [Since 1 pm = 10–12 m]
(b) Number of Zn atoms present in 1.6 cm length
=

1.6

2.6×10−8

= 6.154 × 107

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