NCERT Class XI Chemistry Structure of Atom Solutions

Question : 5

Total: 67

Yellow light emitted from a sodium lamp has a wavelength (λ) of 580 nm. Calculate the frequency (u) and wavenumber (n) of the yellow light.

Solution:

Wavelength of yellow light = 580 nm
= 580 × 10–9 m [Since 1 nm = 10–9 m]
Frequency (u) =

,
where c = velocity of light = 3.0 × 108 m s–1, λ = wavelength of sodium lamp
u =

3.0×108

580×10−9

= 5.17 × 1014s−1
Again, wavenumber (

−

) =

580×10−9m

= 1.724 × 106m−1

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