NCERT Class XI Chemistry Structure of Atom Solutions

Question : 6

Total: 67

Find energy of each of the photons which
(i) corresponds to light of frequency 3 × 1015 Hz.
(ii) have wavelength of 0.50 Å.

Solution:

(i) We know that, E = hυ
where E = energy of photons, h = Planck’s constant, υ = frequency of light
∴ E = hυ = 6.626 × 10–34 × 3 × 1015 = 1.99 × 10–18 J
(ii) E =

where c = velocity of light, h = Planck’s constant, λ = wavelength
E =

6.626×10−34×3×108

0.50×10−10

= 3.98 × 10−15J

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