NCERT Class XI Chemistry Structure of Atom Solutions
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Question : 66
Total: 67
Indicate the number of unpaired electrons in :
(a) P,
(b) Si,
(c) Cr,
(d) Fe and
(e) Kr.
(a) P,
(b) Si,
(c) Cr,
(d) Fe and
(e) Kr.
Solution:
(a)
P → 1 s 2 2 s 2 2 p 6 3 s 2 3 p 3
Number of unpaired electrons = 3
(b)
S i → 1 s 2 2 s 2 2 p 6 3 s 2 3 p 2
Number of unpaired electrons = 2
(c)
C r → 1 s 2 2 s 2 2 p 6 3 s 2 3 p 6 3 d 5 4 s 1
Number of unpaired electrons = 6
(d)
F e → 1 s 2 2 s 2 2 p 6 3 s 2 3 p 6 3 d 6 4 s 2
Number of unpaired electrons = 4
(e)
K r → 1 s 2 2 s 2 2 p 6 3 s 2 3 p 6 3 d 10 4 s 2 4 p 6
Number of unpaired electrons = zero
Number of unpaired electrons = 3
(b)
Number of unpaired electrons = 2
(c)
Number of unpaired electrons = 6
(d)
Number of unpaired electrons = 4
(e)
Number of unpaired electrons = zero
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