NCERT Class XI Chemistry Structure of Atom Solutions

Question : 8

Total: 67

What is the number of photons of light with a wavelength of 4000 pm that provide 1 J of energy?

Solution:

Wavelength of light (λ) = 4000 pm
= 4000 × 10–12 m = 4 × 10–9 m [Since 1 pm = 10–12 m]
E = hu = h ×

6.626×10−34×3×108

4×10−9

= 4.97 × 10−17J
Number of photons providing 1 J of energy =

4.97×10−17

= 2.012 × 1016 photons.

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