NCERT Class XI Chemistry The s-Block Elements Solutions

© examsnet.com
Question : 16
Total: 32
Starting with sodium chloride how would you proceed to prepare
(i) sodium metal
(ii) sodium hydroxide
(iii) sodium peroxide
(iv) sodium carbonate ?
Solution:  
(i) Sodium metal is prepared by electrolysis of fused NaCl at 873 K using iron cathode and graphite anode (Down’s cell).
NaCl ⇌ Na++Cl
At anode : 2Cl2Cl+2eCl2
At cathode : Na++e → Na
(ii) Sodium hydroxide is prepared by electrolysis of aqueous solution of NaCl using Hg cathode and carbon anode.
(Castner-Kellner cell) : NaCl ⇌ Na++Cl
At cathode : Na++e
Hg
Na-amalgam
At anode : Cl
1
2
C
l2
+e

Na - amalgam is treated with water to give NaOH and H2 :
2Na-amalgam + 2H2O2NaOH+2Hg+H2
(iii) Sodium chloride to sodium peroxide : NaCl ⇌ Na++Cl
At anode : 2Cl2Cl+2eCl2
At cathode : Na++e → Na
Sodium is heated in excess of air.
2Na + O2
Δ
Na2O2
.
(iv) Sodium hydrogen carbonate is prepared by passing CO2 through NaCl solution saturated with NH3.NaHCO3 formed is heated to give Na2CO3.
(Solvay process) :
NH3+H2O+CO2 + NaCl → NaHCO3+NH4Cl
2NaHCO3 Na2CO3 + H2O + CO2
© examsnet.com
Go to Question: