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NCERT Class XI Chemistry Thermodynamics Solutions
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Question : 7 of 22
Marks:
+1,
-0
In a process, 701 J of heat is absorbed by a system and 394 J of work is done by the system. What is the change in internal energy for the process?
Solution:
Heat absorbed by the system (q) = 701 J
Work done by the system (w) = –394 J
According to first law of thermodynamics,
DU = q + w = 701 + (–394) = 701 – 394 = 307 J
Work done by the system (w) = –394 J
According to first law of thermodynamics,
DU = q + w = 701 + (–394) = 701 – 394 = 307 J
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