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NCERT Class XI Chemistry Thermodynamics Solutions

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Question : 8
Total: 22
The reaction of cyanamide, NH2CN(s) , with dioxygen was carried out in a bomb calorimeter, and DU was found to be –742.7 kJmol–1 at 298 K. Calculate enthalpy change for the reaction at 298 K.
NH2CN(s)+
3
2
O2(g) → N2(g)+CO2(g)+H2O(l)
Solution:  
NH2CN(s)+
3
2
O2(g) → N2(g)+CO2(g)+H2O(l)
ΔU = - 742.7 kJ/mol
Δn = np−nR = 2 -
3
2
 = +
1
2
 , R =
8.314
1000
 kJK−1mol−1 ; T = 298 K
ΔH = ΔU + ΔnRT = - 742.7 +
1
2
×
8.314
1000
 × 298
= –742.7 + 1.2 = – 741.5 kJ/mol
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