NCERT Class XI Mathematics - Binomial Theorem - Solutions

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Question : 20
Total: 36
Find the 13th term in the expansion of (9x
1
3x
)
18
, x ≠ 0
Solution:  
We know that the (r + 1)th term in the expansion of (x+a)n is given by
tr+1 =
n
Crxnrar

Then (r + 1)th term in the expansion of (9x
1
3x
)
18
is given by
Tr+1 =
18
Cr(9x)18r(
1
3x
)
r

For 13th term, we have r + 1 = 13 i.e., r = 12
T13 =
18
C12(9x)1812(
1
3x
)
12
= 18564 (9x)6
1
312x6
= 18564
96
96
x6
x6
= 18564
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