NCERT Class XI Mathematics - Binomial Theorem - Solutions

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Question : 7
Total: 36
(102)5
Solution:  
We have, 102 = 100 + 2
(102)5 = (100+2)5
=
5
C0(100)5
+
5
C1(100)4(2)
+
5
C2(100)3(2)2
+
5
C3(100)2(2)3
+
5
C4(100)(2)4
+
5
C5(2)5

= (100)5+5(100)4(2) + 10(100)3(4)+10(100)2(8) + 5 (100) (16) + 1 (32)
= 10000000000 + 1000000000 + 40000000 + 800000 + 8000 + 32
= 11040808032.
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