NCERT Class XI Mathematics - Complex Numbers and Quadratic Equations - Solutions

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Question : 41
Total: 52
21x2−28x+10=0
Solution:  
We have , 21x2−28x+10=0
Comparing the given equation with the general form ax2 + bx + c = 0,
we get a = 21, b = – 28, c = 10
∴ x =
−b±√b2−4ac
2a
=
28±√(−28)2−4×21×10
2×21

=
28±√784−840
42
=
28±√−56
42
=
14±√−14
21
=
14±i√14
21

=
14
21
±
i√14
21
=
2
3
±
i√14
21
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