NCERT Class XI Mathematics - Conic Sections - Solutions

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Question : 27
Total: 71
Vertex (0, 0), passing through (5, 2) and symmetric with respect to y- axis.
Solution:  
Since the vertex of the parabola is at (0, 0) and it is symmetrical about the y-axis.
∴ The equation of the parabola is of the form x2 = 4ay
Since the parabola passes through point (5, 2)
∴ (5)2 = 4a × 2 ⇒ 25 = 8a ⇒ a =
25
8
.
The required equation of parabola is x2 =
4×25
8
y
⇒ x2 =
25
2
y

⇒ 2x2 = 25y
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