NCERT Class XI Mathematics - Conic Sections - Solutions
© examsnet.com
Question : 27
Total: 71
Vertex (0, 0), passing through (5, 2) and symmetric with respect to y- axis.
Solution:
Since the vertex of the parabola is at (0, 0) and it is symmetrical about the y-axis.
∴ The equation of the parabola is of the formx 2 = 4ay
Since the parabola passes through point (5, 2)
∴( 5 ) 2 = 4a × 2 ⇒ 25 = 8a ⇒ a =
.
The required equation of parabola isx 2 =
y ⇒ x 2 =
y
⇒2 x 2 = 25y
∴ The equation of the parabola is of the form
Since the parabola passes through point (5, 2)
∴
The required equation of parabola is
⇒
© examsnet.com
Go to Question: