NCERT Class XI Mathematics - Conic Sections - Solutions

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Question : 33
Total: 71
x2
100
+
y2
400
= 1
Solution:  
Given equation of ellipse is
x2
100
+
y2
400
= 1
Clearly, 400 > 100
The equation of ellipse in standard form is
y2
a2
+
x2
b2
= 1
∴ a2 = 400 ⇒ a = 20 and b2 = 100 ⇒ b = 10
We know that
c = √a2−b2 ⇒ c = √400−100 = √300 = 10√3
∴ Coordinates of foci are (0, ± c) i.e. (0, ± 10 √3)
Coordinates of vertices are (0, ± a) i.e. (0, ± 20).
Length of major axis = 2a = 2 × 20 = 40
Length of minor axis = 2b = 2 × 10 = 20
Eccentricity (e) =
c
a
=
10√3
20
=
√3
2

Length of latus rectum =
2b2
a
=
2×100
20
= 10.
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