NCERT Class XI Mathematics - Conic Sections - Solutions

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Question : 37
Total: 71
Vertices (±5, 0), foci (±4, 0)
Solution:  
Clearly, the foci (±4, 0) lie on x-axis.
∴ The equation of ellipse in standard form is
x2
a2
+
y2
b2
= 1
Now vertices are (±5, 0) ⇒ a = 5, foci are (±4, 0) ⇒ c = 4
Also, we know that c2 = a2b2
(4)2 = (5)2b2b2 = 25 – 16 = 9.
Hence the required equation of ellipse is
x2
25
+
y2
9
= 1
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