NCERT Class XI Mathematics - Conic Sections - Solutions

© examsnet.com
Question : 41
Total: 71
Ends of major axis (0,± 5), ends of minor axis (±1, 0)
Solution:  
Since, ends of major axis (0, ± 5) lie on y-axis.
∴ The equation of ellipse in standard form is
x2
a2
+
y2
b2
= 1
Now, ends of major axis =(0,± 5) ⇒ a = 5
Ends of minor axis = (± 1, 0) ⇒ b = 1
Hence, required equation of ellipse is
x2
a
+
y2
5
= 1
© examsnet.com
Go to Question: