Since the foci (0, ±6) lie on y-axis.
∴ The equation of ellipse in standard form is

x2

a2

+

y2

b2

= 1
Now, length of minor axis 2b = 16 ⇒ b = 8, Foci are (0, ±6) ⇒ c = 6
we know that c2 = a2–b2
∴ (6)2 = a2–(8)2 ⇒ a2 = 36 + 64 = 100.
Hence the required equation of ellipse is

x2

64

+

y2

100

= 1.