Test Index

NCERT Class XI Mathematics - Limits and Derivatives - Solutions

© examsnet.com
Question : 21
Total: 72
lim
x→0
(cosecx−cotx)
Solution:  
We have,
lim
x→0
(cosecx−cotx)
=
lim
x→0
[
1−cosx
sinx
] =
lim
x→0
1−1+2sin2(
x
2
)
2sin
x
2
cos
x
2
=
lim
x→0
sin
x
2
cos
x
2
 =
lim
x→0
tan(
x
2
) = 0.
© examsnet.com
Go to Question:
Prev Question
Next Question