NCERT Class XI Mathematics - Limits and Derivatives - Solutions

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Question : 60
Total: 72
sinx+cosx
sinxcosx
Solution:  
Let f (x) =
sinx+cosx
sinxcosx
... (i)
Differentiating (i) with respect to x, we get
d
dx
(f (x)) =
(sinxcosx)(sinx+cosx)(sinx+cosx)(sinxcosx)
(sinxcosx)2

=
(sinxcosx)(cosxsinx)(sinx+cosx)(cosx+sinx)
(sinxcosx)2

=
sinxcosxsin2xcos2x+cosxsinx[sinx+cosx]2
(sinxcosx)2

=
2
(sinxcosx)2

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