NCERT Class XI Mathematics - Limits and Derivatives - Solutions

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Question : 67
Total: 72
(ax2+sinx)(p+qcosx)
Solution:  
Let f (x) = (ax2+sinx)(p+qcosx) ... (i)
Differentiating (i) with respect to x, we get
d
dx
[f (x)] = (ax2+sinx)(p+qcosx) + (p+qcosx)(ax2+sinx)
= (2ax + cos x) (p + q cos x) + (– q sin x) (ax2 + sin x)
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