NCERT Class XI Mathematics - Limits and Derivatives - Solutions
© examsnet.com
Question : 71
Total: 72
Solution:
Let f (x) =
⇒ f (x) =x ( 1 + t a n x ) − 1
Differentiating (i) with respect to x, we get
( 1 + t a n x ) − 1 x ( s e c 2 x ) ( − 1 ) ( 1 + t a n x ) − 2
=( 1 + t a n x ) − 1 x ( s e c 2 x ) ( 1 + t a n x ) − 2
=
−
=
⇒ f (x) =
Differentiating (i) with respect to x, we get
=
=
=
© examsnet.com
Go to Question: