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NCERT Class XI Mathematics - Limits and Derivatives - Solutions

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Question : 70
Total: 72
x2cos(
π
4
)
sinx
Solution:  
Let f (x) =
x2cos(
π
4
)
sinx
 ... (i)
Differentiating (i) with respect to x, we get
d
dx
 [f (x)] = cos
π
4
[
sinx.(x2)′−(x2)(sinx)′
sin2x
]
= cos(
π
4
)[
sinx.2x−x2cosx
sin2x
]
= xcos
π
4
[
2sinx−xcosx
sin2x
]
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