NCERT Class XI Mathematics - Limits and Derivatives - Solutions

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Question : 73
Total: 72
x
sinnx
Solution:  
Let f (x) =
x
sinnx
... (i)
Differentiating (i) with respect to x, we get
d
dx
[f (x)] =
sinnx.1x.nsinn1xcosx
(sinnx)2

=
(sinx)n1(sinxnxcosx)
(sinx)2n

=
sinxnxcosx
(sinx)2nn+1

=
sinxnxcosx
(sinx)n+1
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