NCERT Class XI Mathematics - Linear Inequalities - Solutions

Question : 23

Total: 65

Find all pairs of consecutive odd positive integers both of which are smaller than 10, such that their sum is more than 11.

Solution:

Let x be the smaller of the two odd positive integers. Then the other integer is x + 2. We should have x + 2 < 10 and x + (x + 2) > 11 or, 2x + 2 > 11 or, 2x > 11 – 2 or, 2x > 9 or, x >

Hence, if one number is 5 (odd number), then the other is 7. If the smaller number is 7, then the other is 9. Hence, possible pairs are (5, 7) and (7, 9).

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