NCERT Class XI Mathematics - Linear Inequalities - Solutions
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Question : 4
Total: 65
Solve 3x + 8 > 2, when
(i) x is an integer
(ii) x is a real number.
(i) x is an integer
(ii) x is a real number.
Solution:
Given inequality is 3x + 8 > 2
Transposing 8 to R.H.S., we get 3x > 2 – 8 = –6
Dividing both sides by 3, we get x > –2
(i) When x is an integer, the solution is {–1, 0, 1, 2, 3, ...}
(ii) When x is real, the solution is (–2, ∞).
Transposing 8 to R.H.S., we get 3x > 2 – 8 = –6
Dividing both sides by 3, we get x > –2
(i) When x is an integer, the solution is {–1, 0, 1, 2, 3, ...}
(ii) When x is real, the solution is (–2, ∞).
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