6 ≤ –3(2x – 4) < 12
⇒

6

3

≤ - (2x - 4) <

12

3

(Divide by 3) ⇒ 2 ≤ – (2x – 4) < 4 ⇒ 2 ≤ –2x + 4 < 4
⇒ 2 – 4 ≤ –2x + 4 – 4 < 4 – 4 (Subtract 4) or –2 ≤ –2x < 0
⇒

−2

−2

≥

−2x

−2

> 0 (Divide each side by –2) ⇒ 1 ≥ x > 0
Hence, x is less than or equal to ‘1’ and greater than 0, i.e., x ∈ (0, 1]