NCERT Class XI Mathematics - Permutations and Combinations - Solutions
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Question : 37
Total: 41
In an examination, a question paper consists of 12 questions divided into two parts i.e., Part I and Part II, containing 5 and 7 questions, respectively. A student is required to attempt 8 questions in all, selecting at least 3 from each part. In how many ways can a student select the questions ?
Solution:
Since at least 3 questions are required to attempt from each part.
Therefore a student can attempt
(a) 3 questions from part I & 5 questions from part II
(b) 4 questions from part I & 4 questions from part II
(c) 5 questions from part I & 3 questions from part II
In case (a), selection can be made in
C 3 ×
C 5 ways.
In case (b), selection can be made in
C 4 ×
C 4 ways.
In case (c), selection can be made in
C 5 ×
C 3 ways.
∴ The required no. of ways =
C 3 ×
C 5 +
C 4 ×
C 4 +
C 5 ×
C 3 =
×
+
×
+
×
=
×
+ 5 ×
+ 1 ×
= 210 + 175 + 35 = 420
Therefore a student can attempt
(a) 3 questions from part I & 5 questions from part II
(b) 4 questions from part I & 4 questions from part II
(c) 5 questions from part I & 3 questions from part II
In case (a), selection can be made in
In case (b), selection can be made in
In case (c), selection can be made in
∴ The required no. of ways =
=
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