NCERT Class XI Mathematics - Probability - Solutions
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Question : 36
Total: 54
Fill in the blanks in following table :
| S.No | P (A) | P (B) | P (A ∩ B) | P (A ∪ B) | ||||||
|---|---|---|---|---|---|---|---|---|---|---|
| (i) | | ... | ||||||||
| (ii) | 0.35 | ... | 0.25 | 0.6 | ||||||
| (iii) | 0.5 | 0.35 | ... | 0.7 |
Solution:
(i) P(A ∪ B) = P(A) + P(B) – P(A ∩ B)
=
+
−
(ii) P(A ∪ B) = P(A) + P(B) – P(A ∩ B) ⇒ 0.6 = 0.35 + P(B) – 0.25
∴ P(B) = 0.6 – 0.35 + 0.25 = 0.5
(iii) P(A ∪ B) = P(A) + P(B) – P(A ∩ B) ⇒ 0.7 = 0.5 + 0.35 – P(A ∩ B)
∴ P(A ∩ B) = 0.5 + 0.35 – 0.7 = 0.15
=
(ii) P(A ∪ B) = P(A) + P(B) – P(A ∩ B) ⇒ 0.6 = 0.35 + P(B) – 0.25
∴ P(B) = 0.6 – 0.35 + 0.25 = 0.5
(iii) P(A ∪ B) = P(A) + P(B) – P(A ∩ B) ⇒ 0.7 = 0.5 + 0.35 – P(A ∩ B)
∴ P(A ∩ B) = 0.5 + 0.35 – 0.7 = 0.15
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