NCERT Class XI Mathematics - Probability - Solutions

© examsnet.com
Question : 38
Total: 54
If E and F are events such that P(E) =
1
4
, P (F) =
1
2
and P(E and F) =
1
8
, find (i) P(E or F), (ii) P(not E and not F).
Solution:  
(i) P(E or F) = P(E ∪ F)
= P(E) + P(F) – P(E ∩ F) =
1
4
+
1
2
1
8
=
2+41
8
=
5
8

(ii) not E and not F = E′ ∩ F′ = (E ∪ F)′ (De Morgan’s Law)
\ P(not E and not F) = P(E ∪ F)′ = 1 - P (E ∪ F) = 1 -
5
8
=
3
8

© examsnet.com
Go to Question: