NCERT Class XI Mathematics - Probability - Solutions
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Question : 38
Total: 54
If E and F are events such that P(E) =
, P (F) =
and P(E and F) =
, find (i) P(E or F), (ii) P(not E and not F).
Solution:
(i) P(E or F) = P(E ∪ F)
= P(E) + P(F) – P(E ∩ F) =
+
−
=
=
(ii) not E and not F = E′ ∩ F′ = (E ∪ F)′ (De Morgan’s Law)
\ P(not E and not F) = P(E ∪ F)′ = 1 - P (E ∪ F) = 1 -
=
= P(E) + P(F) – P(E ∩ F) =
(ii) not E and not F = E′ ∩ F′ = (E ∪ F)′ (De Morgan’s Law)
\ P(not E and not F) = P(E ∪ F)′ = 1 - P (E ∪ F) = 1 -
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