NCERT Class XI Mathematics - Probability - Solutions
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Question : 49
Total: 54
In a certain lottery 10,000 tickets are sold and ten equal prizes are awarded. What is the probability of not getting a prize if you buy
(a) one ticket (b) two tickets (c) 10 tickets.
(a) one ticket (b) two tickets (c) 10 tickets.
Solution:
Total number of tickets = 10,000
Number of prize bearing tickets = 10
Number of non prize bearing tickets = 10,000 – 10 = 9990
(a) Let E be the event that one ticket is not prize bearing ticket.
n (E) =
C 1
∴ P (E) =
(b) Let F be the event that two tickets are not prize bearing tickets.
n (F) =
C 2
∴ P (F) =
(c) Let G be the event that ten tickets are not prize bearing tickets.
n (G) =
C 10
∴ P (G) =
Number of prize bearing tickets = 10
Number of non prize bearing tickets = 10,000 – 10 = 9990
(a) Let E be the event that one ticket is not prize bearing ticket.
n (E) =
∴ P (E) =
(b) Let F be the event that two tickets are not prize bearing tickets.
n (F) =
∴ P (F) =
(c) Let G be the event that ten tickets are not prize bearing tickets.
n (G) =
∴ P (G) =
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