NCERT Class XI Mathematics - Relations and Functions - Solutions
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Question : 28
Total: 36
Find the domain and the range of the real function f defined by
f (x) =√ ( x − 1 )
f (x) =
Solution:
Given f (x) = √ ( x − 1 )
We know (x – 1) ≥ 0 ⇒ x ≥ 1 ⇒ x ∈ [1, ∞)
∴ Domain of f (x) is [1, ∞)
Let y = f (x) =√ ( x − 1 ) √ ( x − 1 ) y 2
∴ Range of f (x) is [0, ∞)
We know (x – 1) ≥ 0 ⇒ x ≥ 1 ⇒ x ∈ [1, ∞)
∴ Domain of f (x) is [1, ∞)
Let y = f (x) =
∴ Range of f (x) is [0, ∞)
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