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NCERT Class XI Mathematics - Sequences and Series - Solutions

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Question : 10
Total: 106
an =
n(n−2)
n+3
;a20
Solution:  
We have, an =
n(n−2)
n+3
;a20
Put n = 20, a20 =
20(20−2)
20+3
 =
20×18
23
 =
360
23
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