NCERT Class XI Mathematics - Statistics - Solutions

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Question : 22
Total: 34
The diameters of circles (in mm) drawn in a design are given below:
Diameters 33 - 36 37 - 4041 - 44 45 - 4849 - 52
No. of circles 15 1721 22 25

Calculate the standard deviation and mean diameter of the circles.
[Hint : First make the data continuous by making the classes as 32.5 – 36.5, 36.5 – 40.5, 40.5 – 44.5, 44.5 – 48.5, 48.5 – 52.5 and then proceed.]
Solution:  
Diameters Modified ClassesMid values
xi
fi ui =
xi42.5
4
fiui fiui2
33 - 3632.5 - 36.5 34.5 15 - 2 - 30 60
37 - 40 36.5 - 40.5 38.5 17 - 1 - 1717
41 - 4440.5 - 44.542.521 00 0
45 - 4844.5 - 48.5 46.5 22 1 22 22
49 - 5248.5 - 52.5 50.525 2 50100
100 25 199

Let assumed mean (A) = 42.5
Mean (
x
)
= A +
Σfiui
N
× h = 42.5 +
25
100
× 4 = 42.5 + 1 = 43.5
Standard deviation (σ) =
h
N
NΣfiui2(Σfiui)2

=
4
100
100×199(25)2
=
1
25
19275
=
1
25
× 138.83 = 5.55
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