NCERT Class XI Mathematics - Statistics - Solutions

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Question : 27
Total: 34
The sum and sum of squares corresponding to length x (in cm) and weight y (in gm) of 50 plant products are given below :
50
Σ
i=1
xi
= 212 ,
50
Σ
i=1
xi2
= 902.8 ;
50
Σ
i=1
yi
= 261 ,
50
Σ
i=1
yj2
= 1457.6
Which is more varying, the length or weight?
Solution:  
We have ,
50
Σ
i=1
xi
= 212 ,
50
Σ
i=1
xi2
= 902.8
Now,
x
=
212
50
= 4.24
σx2 =
1
50
× 902.8 - (
212
50
)
2

= 18.056 – 17.978 = 0.078
σx = 0.078 = 0.28
Also,
50
Σ
i=1
yi
= 261 ,
50
Σ
i=1
yj2
= 1457.6
y
=
261
50
= 5.22
σy2 =
1
50
× 1457.6 - (
261
50
)
2
= 29.152 - 27.248 = 1.904
σy = 1.904 = 1.38
C.V. of length (x) =
0.28
4.24
× 100 = 6.6
C.V. of weight (y) =
1.38
5.22
× 100 = 26.4
Since C.V. of weight > C.V. of length
Thus weight have more variability than length.
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