NCERT Class XI Mathematics - Statistics - Solutions

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Question : 28
Total: 34
The mean and variance of eight observations are 9 and 9.25, respectively. If six of the observations are 6, 7, 10, 12, 12 and 13, find the remaining two observations.
Solution:  
Let the remaining two observations be x and y. Then we are given that
6+7+10+12+12+13+x+y
8
= 9
⇒ 60 + x + y = 72 ⇒ x + y = 12 ... (i)
Also,
1
8
(62+72+102+122+122+132+x2+y2)
(9)2
= 9.25
1
8
(36+49+100+144+144+169+x2+y2)
(81)
= 9.25
⇒ 642 + x2+y2 = 722
x2+y2 = 80 ... (ii)
Now (x+y)2+(xy)2 = 2(x2+y2)
(12)2+(xy)2 = 2 × 80 [Using (i) & (ii)]
(xy)2 = 160 – 144 ⇒ (xy)2 = 16 ⇒ x – y = ± 4
When x – y = 4 and x + y = 12, we get x = 8 and y = 4
When x – y = – 4 and x + y = 12, we get x = 4 and y = 8.
So, the remaining two observations are 4 and 8.
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